**From:** J. Andrew Rogers (*andrew@ceruleansystems.com*)

**Date:** Sun Jun 22 2008 - 23:38:54 MDT

**Next message:**J. Andrew Rogers: "Re: [sl4] Is there a model for RSI?"**Previous message:**Peter de Blanc: "Re: [sl4] Is there a model for RSI?"**In reply to:**Peter de Blanc: "Re: [sl4] Is there a model for RSI?"**Next in thread:**J. Andrew Rogers: "Re: [sl4] Is there a model for RSI?"**Reply:**J. Andrew Rogers: "Re: [sl4] Is there a model for RSI?"**Reply:**Peter de Blanc: "Re: [sl4] Is there a model for RSI?"**Reply:**Vladimir Nesov: "Re: [sl4] Is there a model for RSI?"**Messages sorted by:**[ date ] [ thread ] [ subject ] [ author ] [ attachment ]

On Jun 22, 2008, at 10:21 PM, Peter de Blanc wrote:

*> If you'll look at the program I supplied, you'll notice a 0 at the
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*> end. If you run the program, it'll output a near-copy of itself,
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*> different only in that the 0 has been replaced with a 1. In general,
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*> program N will output a near-copy of itself, except the N at the end
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*> will be replaced with N+1.
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If your "counter" does not occupy memory then the complexity is

constant. If it does occupy memory, it is eating bits as N grows on a

finite machine. Either way, you have a problem.

All that aside, your assertion is contrary to some pretty rudimentary

(for this list) theorems in mathematics. Without inspecting your

argument, that alone should have suggested something was amiss.

J. Andrew Rogers

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