**From:** Eric Burton (*brilanon@gmail.com*)

**Date:** Mon Mar 12 2012 - 11:45:08 MDT

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Actually you might do the sums of three runs in a row not two, to see

it. Here it is in short

*> 1 2 4 8 16 32 64 128 256 512 1024 2048 4096 8192
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*> highest
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*> run
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*> 1 2 4 8 7 5 10 11 13 8 7 14 19 20
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*> highest
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*> run
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*> 1 2 4 8 7 5 1 2 4 8 7 5 10 2 2 4 8 7 5 10 2
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*> highest
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*> run
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1 2 4 8 7 5 1 2 4 8 7 5 1 2 2 4 8 7 5 1 2 5 1

2 2 4 8 7 5 1 2

So you take the sums of the digits in powers of 2. The sums of the

digits in that. And the sums of the digits in -that-. You get the

magic 487-512 number where, every sum is a single digit and there is

no further series to produce.

Oh no wow

I have some chocolate in the fridge

On Mon, Mar 12, 2012 at 1:41 PM, Eric Burton <brilanon@gmail.com> wrote:

*> Thanks tom. This 487 512 thing. I'm stuck on it. Look
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*>
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*> 12 487 512 487 512 487 512 487
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*> 512 487 512 487 512 4487 512 487
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*>
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*> Then a six
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*>
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*> I don't know dude like if you take the sums of the digits of powers of 2
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*>
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*> Then the sums of the digits in the results
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*>
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*> You get that O_O printed for a long time
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*>
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*> I mean really wow
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*>
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*> But I will stop
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*>
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*> I should get a blog...
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